Let p be the number 2/3 kg pieces that are cut from a 4 kg cake. So, p × (2/3) = 4 p = 4 × (3/2) = 2 × 3 = 6

Given fraction: 5/129 Here, numerator = 5 Denominator = 129 Reciprocal of 5/129 = 129/5 The product of 5/129 and its reciprocal = (5/129) × (129/5) = 1.

Length of cloth Sunita has = 3/4 m According to the given, Sunita has 3/4 m of cloth, and she gave 1/3 of it to Rehana. Therefore, the length of cloth Rehana has = 1/3 of 3/4 m = (1/3) x (3/4) m = 1/4 m

Let m be the whole work to be done. The part of work done by Anuradha in 6 hours = m Thus, the part of work done by her in 1 hour = m/6 The part of work done by her in 5 hours = (m/6) x 5 = 5m/6 The part of work done by her in 6 hours = (m/6) x 6 = m Therefore, Anuradha can do 1/6 part of work in 1 hour, 5/6 part of work in 5 hours and the complete work in 6 hours.

(i) (⅖) × 5 ¼ Here, 5 ¼ is a mixed fraction. Let us convert this mixed fraction into an improper fraction. 5 ¼ = [(5 × 4) + 1]/4 = 21/4 Thus, (⅖) × 5 ¼ = (⅖) × (21/4) = 21/10 (ii) 2 ⅗ × 3 Here, 2 ⅗ is a mixed fraction. Let us convert this mixed fraction into an improper fraction. 2 ⅗ = [(2 × 5) + 3]/5 = 13/5 Therefore, 2 ⅗ × 3 = (13/5) × 3 = 39/5